Reaction of tris(hydroxymethyl)phosphine and cinnamaldehyde in methanol

JOURNAL OF HETEROCYCLIC CHEMISTRY(2020)

引用 2|浏览9
暂无评分
摘要
Reaction of tris(hydroxymethyl)phosphine with excess cinnamaldehyde in CH3OH or CD3OD, followed using NMR, proceeds via several phosphorus-containing intermediates, multiple transformations of organic parts, and with the solvent H/D isotope effect on products. In both solvents, one CH2OH group of tris(hydroxymethyl)phosphine is readily replaced by the cinnamaldehyde moiety to give the primary product, a 1,3-oxaphosphorinane derivative. Slower replacement of the second CH2OH group leads to a mixture of aliphatic and heterocyclic phosphine intermediates in a ratio of 4:1 in CH3OH and 1:1 in CD3OD; both intermediates contain alcohol and aldehyde groups and convert rapidly into intra- and intermolecular hemiacetals. The hemiacetals of the aliphatic phosphine rearrange further into an unsymmetrical trialkylphosphine oxide, whereas the hemiacetals of the heterocyclic phosphine react with the third mole of cinnamaldehyde to replace the third CH2OH group of tris(hydroxymethyl)phosphine. All intermediates and products are formed as mixtures of stereoisomers.
更多
查看译文
AI 理解论文
溯源树
样例
生成溯源树,研究论文发展脉络
Chat Paper
正在生成论文摘要