A study of the $$^{11}$$ B( $$^{3}$$ He,d) $$^{12}$$ C reaction at incident $$^{3}$$ He energy $$\hbox {E}_{{lab}}$$ = 25 MeV has been performed at the K-130 cyclotron at the University of Jyväskylä, Finland. Differential cross sections have been measured for the 13.35 MeV state and for the states with excitation energy around 20 MeV in $$^{12}$$ C. The data were analyzed with the DWBA method. A tentative assignment, 4 $$^{-}$$ , is given for the state at 13.35 MeV in a joint study of the reaction and inelastic scattering of $$\alpha $$ -particles with the energy of 110 MeV. For the state at 20.98 MeV, the possible spin-parity 3 $$^{-}$$ and the isospin T = 0 are assigned for the first time. Our model description of the broad state at 21.6 MeV is consistent with the previous assignments of isospin T = 0 and spin-parity of 2 $$^{+}$$ or 3 $$^{-}$$ . The excited state at 22.4 MeV may have possible spin-parities of either 6 $$^{+}$$ or 5 $$^{-}$$ . The collected statistics was insufficient to solve this question. Rotational bands which can exist in $$^{12}$$ C were presented.

An experiment on the scattering of 23 MeV deuterons by $$^{9}$$ Be nucleus was carried out. Differential scattering cross sections are obtained for the following states: g.s., 1.68 MeV, 2.43 MeV, 2.78 MeV, 3.05 MeV, 3.82 MeV, 4.70 MeV, 5.59 MeV, 6.38 MeV, 6.76 MeV and 7.94 MeV. The obtained data were analyzed using the distorted wave Born approximation (DWBA) and modified diffraction model (MDM). It was confirmed that the positive parity band $$K^{\pi }$$ = $${\frac{1}{2}}^{+}$$ based on the 1.68 MeV, $${\frac{1}{2}}^{+}$$ state is formed by the 3.05 MeV, $${\frac{5}{2}}^{+}$$ ; 4.70 MeV, $${\frac{3}{2}}^{+}$$ and 6.76 MeV, $${\frac{9}{2}}^{+}$$ states. It was proposed that the 3rd band ( $$K^{\pi }$$ = $${\frac{1}{2}}^{-}$$ ) based on the 2.78 MeV, $${\frac{1}{2}}^{-}$$ state may be formed by the 5.59 MeV, $${\frac{3}{2}}^{-}$$ and 7.94 MeV, $${\frac{5}{2}}^{-}$$ states. The radii of these band states ( $$K^{\pi }$$ = $${\frac{1}{2}}^{+}$$ and $$K^{\pi }$$ = $${\frac{1}{2}}^{-}$$ ) are increased compared to the ground state. Besides, it is found that the 3.82 MeV state has $$J^{\pi }$$ = $${\frac{3}{2}}^{-}$$ and does not belong to any of the rotational bands considered above. Possibly, it is formed as a one-particle state near the excited $$^{8}$$ Be core with the spin $$J_{c}$$ = 2.